Rust by Example

17.1 Box, stack and heap

All values in Rust are stack allocated by default. Values can be boxed (allocated in the heap) by creating a Box<T>. A box is a smart pointer to a heap allocated value of type T. When a box goes out of scope, its destructor is called, the inner object is destroyed, and the memory in the heap is freed.

Boxed values can be dereferenced using the * operator; this removes one layer of indirection.

use std::mem;

#[derive(Clone, Copy)]
struct Point {
    x: f64,
    y: f64,

struct Rectangle {
    p1: Point,
    p2: Point,

fn origin() -> Point {
    Point { x: 0.0, y: 0.0 }

fn boxed_origin() -> Box<Point> {
    // Allocate this point in the heap, and return a pointer to it
    Box::new(Point { x: 0.0, y: 0.0 })

fn main() {
    // (all the type annotations are superfluous)
    // Stack allocated variables
    let point: Point = origin();
    let rectangle: Rectangle = Rectangle {
        p1: origin(),
        p2: Point { x: 3.0, y: 4.0 }

    // Heap allocated rectangle
    let boxed_rectangle: Box<Rectangle> = Box::new(Rectangle {
        p1: origin(),
        p2: origin()

    // The output of functions can be boxed
    let boxed_point: Box<Point> = Box::new(origin());

    // Double indirection
    let box_in_a_box: Box<Box<Point>> = Box::new(boxed_origin());

    println!("Point occupies {} bytes in the stack",
    println!("Rectangle occupies {} bytes in the stack",

    // box size = pointer size
    println!("Boxed point occupies {} bytes in the stack",
    println!("Boxed rectangle occupies {} bytes in the stack",
    println!("Boxed box occupies {} bytes in the stack",

    // Copy the data contained in `boxed_point` into `unboxed_point`
    let unboxed_point: Point = *boxed_point;
    println!("Unboxed point occupies {} bytes in the stack",